Math101learn.math101.caIncreasing and Decreasing Functions
A rigorous, example-driven guide to increasing and decreasing functions, including hypotheses, method choice, verification, and practice.
The central idea
If $f$ is differentiable on an interval, $f'(x)>0$ throughout that interval implies $f$ is increasing there, while $f'(x)<0$ implies it is decreasing. Critical numbers in the domain, where $f'=0$ or $f'$ does not exist, partition the domain into intervals on which the derivative's sign can be tested.
Definitions, hypotheses, and notation
The derivative-sign implications rely on the Mean Value Theorem. If $x_1<x_2$ lie in an interval where $f'>0$, then $f(x_2)-f(x_1)=f'(c)(x_2-x_1)>0$ for some intermediate $c$, so the function is increasing. This argument shows why differentiability on the interval, not one positive sample derivative, supports the conclusion.
A derivative may equal zero at isolated points without destroying strict increase; $x^3$ is strictly increasing despite $f'(0)=0$. Sign charts use test points only after factoring or continuity of $f'$ shows the sign cannot change inside the subinterval. Repeated roots of $f'$ often preserve sign, while odd-multiplicity roots often reverse it.
Conceptual meaning
The derivative is local slope. Positive slope means outputs rise as inputs move right; negative slope means they fall. A zero derivative at one point does not by itself establish a maximum, minimum, or even a change in monotonicity.
A dependable method and decision rule
- Determine the domain of the original function.
- Compute $f'$ and find all critical numbers in that domain.
- Include domain breaks as interval boundaries without calling excluded points critical numbers.
- Make a sign chart by testing one point in every resulting open interval.
- Translate positive intervals to increasing and negative intervals to decreasing.
Fully worked example
Graphical or geometric meaning
A derivative sign chart is a compressed sketch of the graph's motion. Arrows point up on positive-sign intervals and down on negative-sign intervals. Only the sign on an entire interval, not the value at one sample point alone, supports the conclusion.
Common mistakes and why they fail
Verification and reasonableness checks
- Plot a few function values to confirm the sign chart's direction.
- Factor $f'$ and track multiplicities at its zeros.
- Verify each claimed interval lies inside the original domain.
Sign charts describe intervals
Find where $f'$ is zero or undefined, retain values in the domain of $f$, and use them to partition that domain. Testing the sign of $f'$ on each open interval determines monotonicity. A critical point does not automatically give an extremum: if the derivative keeps the same sign, the function continues in the same direction. Endpoints still matter for absolute extrema on a closed interval even though two-sided derivatives are unavailable there. Also inspect the original formula before merging intervals. Cancellation in a simplified derivative can hide a hole or vertical asymptote inherited from $f$, and monotonicity intervals cannot cross such a domain break.
Practice
- Where is $x^2$ decreasing?
- Where is $x^2$ increasing?
- Does $f'(2)=0$ alone prove an extremum?
Answers and brief solutions
- $(-\infty,0)$.
- $(0,\infty)$.
- No.
Connections and next steps
Explore the idea
Tangent and accumulation explorer
Change one quantity at a time and connect what moves to Increasing and Decreasing Functions.
Try it yourself
Hints are part of learning. Open one whenever it makes the next step feel possible.
For f(x)=x³−3x, on which interval is f decreasing?
- f′=3(x−1)(x+1).
- This product is negative between its roots.
- Thus f decreases on (−1,1).
End of lesson
Nice work making it this far.
Understanding grows through return visits. Save this lesson, try the practice, or continue when you are ready.
