Math101learn.math101.caAntiderivatives
A rigorous, example-driven guide to antiderivatives, including hypotheses, method choice, verification, and practice.
The central idea
An antiderivative of a function $f$ on an interval $I$ is a differentiable function $F$ satisfying $F'(x)=f(x)$ for every $x\in I$. The notation $\int f(x)\,dx=F(x)+C$ represents the entire family, not one function. On an interval, any two antiderivatives of the same $f$ differ by a constant.
Definitions, hypotheses, and notation
The interval in the definition matters. The function $1/x$ has $\ln x+C$ as an antiderivative on $(0,\infty)$ and $\ln(-x)+C$ on $(-\infty,0)$; constants chosen on the two disconnected pieces need not agree. For a continuous integrand on one interval, however, the constant-difference theorem follows from the Mean Value Theorem: if $F'=G'$, then $(F-G)'=0$, so $F-G$ is constant. This explains both the $+C$ convention and its scope.
Antiderivatives also encode qualitative information. If $f\ge 0$, every antiderivative of $f$ is nondecreasing, and if $f>0$ throughout, it is strictly increasing. If $f$ is differentiable and nondecreasing, then $f'\ge 0$, so $F''=f'\ge 0$ and every antiderivative is convex. Initial-value problems use one point to set vertical position, while definite integrals use endpoint subtraction so the arbitrary constant disappears. These are two different ways of resolving the same family of vertically translated solutions.
Conceptual meaning
Differentiation forgets vertical position: every graph $y=F(x)+C$ has the same slopes. Antidifferentiation reconstructs the possible height profiles from those slopes. An initial condition such as $F(0)=3$ selects one member of the vertically translated family.
A dependable method and decision rule
- Rewrite roots and reciprocals as powers when that makes the power rule visible.
- Integrate term by term, using $\int x^n dx=x^{n+1}/(n+1)$ only when $n\ne-1$.
- Use $\int x^{-1}dx=\ln|x|+C$ for the exceptional exponent $-1$.
- Attach one arbitrary constant $C$ after integrating the whole expression.
- Differentiate the result; then use any initial value to determine $C$.
Fully worked example
Graphical or geometric meaning
The graphs of $2x^3-4\ln x+C$ are vertical translations. At each fixed $x>0$ their tangent lines are parallel because changing $C$ changes height but not slope. The sign of $f$ tells where every antiderivative rises or falls.
Common mistakes and why they fail
Verification and reasonableness checks
- Differentiate the proposed antiderivative and simplify to the original integrand.
- Check the interval before simplifying $\ln|x|$.
- If an initial condition is given, substitute it into the final function.
A shape check before solving
An antiderivative carries geometric information as well as algebra. If $F'=f$ and $f\ge0$ on an interval, then $F$ is nondecreasing there; if $f>0$ throughout, $F$ is strictly increasing. If $f$ is differentiable and $f'\ge0$, then $F''=f'\ge0$, so $F$ is convex. These checks do not determine the additive constant: an initial value such as $F(a)=b$ still selects one curve from the family $F+C$. Predict sign and rough shape before integrating, then differentiate the candidate and compare those predictions. This catches sign errors, especially when $f$ changes sign or has a zero where strict increase cannot be asserted.
Practice
- Find $\int(3x^2-2x+4)\,dx$.
- Find $\int 5/x\,dx$ on an interval not containing zero.
- If $G'(x)=2x$ and $G(2)=7$, find $G(x)$.
Answers and brief solutions
- $x^3-x^2+4x+C$.
- $5\ln|x|+C$.
- $G=x^2+3$.
Connections and next steps
Explore the idea
Tangent and accumulation explorer
Change one quantity at a time and connect what moves to Antiderivatives.
Try it yourself
Hints are part of learning. Open one whenever it makes the next step feel possible.
If F′(x) = 6x² and F(0) = 4, which function is F?
- An antiderivative of 6x² is 2x³ + C.
- F(0)=C=4.
- Therefore F(x)=2x³+4.
End of lesson
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