Math101learn.math101.caChain Rule
The chain rule differentiates a function inside another by multiplying the outer rate by the inner rate.
When one quantity changes through another, their rates multiply.
Composite structure
A composite function has form
The inner function $g$ acts first, and the outer function $f$ acts on its output. Differentiation must account for how fast both layers change.
The rule
The chain rule states
In Leibniz notation, if $y=f(u)$ and $u=g(x)$,
The notation resembles cancellation and correctly tracks rates through the chain.
Outer-then-inner routine
- Identify the outer function and leave its input unchanged.
- Differentiate the outer function.
- Multiply by the derivative of the inner function.
- Repeat if more layers remain.
This avoids expanding expressions that were designed to stay composed.
Worked example: a power of a polynomial
The factor $6x$ is essential; without it, only the outer layer has been differentiated.
Exponential and trigonometric examples
For $y=e^{4x-7}$,
For $y=\sin(x^2)$,
The original inner expression remains inside the differentiated outer function.
Nested chains
For
there are three layers: square root, sum with a fourth power, and linear inner expression. Write powers:
Then
Each layer contributes one factor.
Chain rule with product or quotient rules
Structure can require several rules. For
use product rule outside and chain rule inside cosine:
Marking the main operation first helps determine the outer rule.
Rate interpretation
Suppose radius $r$ changes with time and area is $A=\pi r^2$. Then
Area changes through radius, so their rates multiply. Units confirm the chain: area per radius times radius per time gives area per time.
Reverse recognition
The chain rule explains why an expression such as
is the derivative of $\sin(x^2)$. Recognizing an inner derivative beside a composite function becomes important in integration.
Common mistakes
Differentiating only the outer function. Multiply by the inner derivative.
Changing the inner expression prematurely. Keep it intact inside $f'$.
Multiplying by the inner function rather than its derivative. Use $g'(x)$.
Missing layers in a nested composite. Trace from outside to inside.
Using chain rule instead of product rule for multiplied functions. Identify the main operation.
Quick self-check
- What is the outermost operation?
- What expression serves as its input?
- Did the differentiated outer function keep that input?
- Is the inner derivative multiplied afterward?
- Are there additional product, quotient, or chain layers?
- Do units or a numerical check support the result?
Related topics
Try it yourself
Hints are part of learning. Open one whenever it makes the next step feel possible.
Differentiate y = (3x² − 1)⁵.
- Outer derivative: 5(3x² − 1)⁴.
- Inner derivative: 6x.
- Multiply to obtain 30x(3x² − 1)⁴.
End of lesson
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