Math101learn.math101.caDerivatives of Exponential Functions
A rigorous, example-driven guide to derivatives of exponential functions, including hypotheses, method choice, verification, and practice.
The central idea
The natural exponential satisfies $d(e^x)/dx=e^x$. For a constant base $a>0$, $a\ne1$, $d(a^x)/dx=a^x\ln a$. With a differentiable exponent $u(x)$, the chain rule gives $d(e^{u})/dx=e^{u}u'$ and $d(a^{u})/dx=a^{u}\ln(a)u'$.
Definitions, hypotheses, and notation
The factor $\ln a$ is forced by rewriting $a^x=e^{x\ln a}$. Differentiating this identity by the chain rule gives $a^x\ln a$, so the natural-base rule and general-base rule are not independent facts. When $0<a<1$, $\ln a<0$, explaining exponential decay without a separate derivative formula. Negative bases are excluded because $a^x$ is not real-valued and continuous for every real exponent.
In a model $P(t)=P_0e^{kt}$, differentiation yields $P'=kP$: growth rate is proportional to current amount. The sign of $k$ determines growth or decay, and $1/k$ sets a characteristic time scale. This relation provides an independent check on symbolic derivatives: after differentiating, the result should retain the exponential factor and have the expected sign.
Conceptual meaning
The function $e^x$ is uniquely normalized to equal its own instantaneous growth rate. Other bases grow in proportion to their current value, with constant of proportionality $\ln a$. Bases between zero and one have negative logarithm and therefore decay.
A dependable method and decision rule
- Identify the entire exponent as the inner function $u$.
- Copy the exponential factor unchanged.
- Include $\ln a$ when the base is not $e$.
- Multiply by $u'$ for a composite exponent.
- Use product or quotient rules too if other factors surround the exponential.
Fully worked example
Graphical or geometric meaning
Every tangent slope of $e^x$ equals the point's height. For $e^{-3x}$, values remain positive but decrease, and the factor $-3$ makes the initial decay three times as steep as that of $e^{-x}$.
Common mistakes and why they fail
Verification and reasonableness checks
- For $a>1$, verify that $a^x\ln a$ is positive.
- Use logarithmic identities or a numerical difference quotient at one point.
- Factor the derivative and check that every product-rule term is present.
Separate the base from the exponent
For $a>0$, $\frac d{dx}a^{u(x)}=a^{u(x)}\ln(a)u'(x)$, whereas $\frac d{dx}e^{u(x)}=e^{u(x)}u'(x)$. The factor $\ln a$ disappears only for base $e$. If both base and exponent vary, as in $u(x)^{v(x)}$, logarithmic differentiation is safer and requires attention to the real-valued domain. A qualitative check uses sign: a positive-base exponential never changes sign, and its derivative has the sign of $\ln(a)u'$. Thus $0<a<1$ reverses the growth direction associated with $u'$. Testing a simple linear exponent can confirm that every chain-rule factor was retained.
Practice
- Differentiate $e^{5x}$.
- Differentiate $2^x$.
- Differentiate $e^{x^2+1}$.
Answers and brief solutions
- $5e^{5x}$.
- $2^x\ln2$.
- $2xe^{x^2+1}$.
Connections and next steps
Try it yourself
Hints are part of learning. Open one whenever it makes the next step feel possible.
Which is the derivative of 3^(2x)?
- Here a=3 and u=2x.
- u′=2.
- The derivative is 3^(2x) ln3 · 2.
End of lesson
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