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AlgebraGrades 9–123 min read

Rational Equations

Rational equations contain variable denominators and are solved by recording restrictions, clearing denominators, and checking candidates.

Cheat sheet
Clearing denominators simplifies the algebra, but it never makes forbidden inputs legal.

Identify restrictions first

A rational equation contains one or more rational expressions. Before manipulating it, find values that make any original denominator zero. These are excluded even if a factor later cancels.

For

$$ \frac2{x-1}+1=\frac5{x-1}, $$

the restriction is $x\ne1$.

Clear denominators with the LCD

Find the least common denominator and multiply every term on both sides by it. This creates an equivalent polynomial equation for allowed inputs.

Write parentheses around numerators before distributing. Skipping a term or part of a numerator changes the equation.

Worked example: a linear result

Worked example: a quadratic result

Solve

$$ \frac1x+\frac1{x-2}=1,qquad x\ne0,2. $$

Multiply by $x(x-2)$:

$$ (x-2)+x=x(x-2). $$

Rearrange:

$$ x^2-4x+2=0. $$

The quadratic formula gives

$$ x=2\pm\sqrt2. $$

Neither value is excluded, so both are valid.

Extraneous solutions

Multiplying by a variable expression can make an excluded value appear as a solution of the cleared equation. Such a value is extraneous because the original equation was undefined there.

Checking restrictions is mandatory; direct substitution also catches algebra errors.

Equations with proportional structure

Some rational equations are proportions:

$$ \frac ab=\frac cd. $$

Cross multiplication gives $ad=bc$ only when $b$ and $d$ are nonzero. Cross multiplication is simply multiplication by the common denominator—it does not remove the need for restrictions.

Equations with no solution

After clearing denominators, an equation may reduce to a false statement such as $3=7$, indicating no solution. A candidate set may also consist only of excluded values, again leaving no solution.

If the result is an identity such as $0=0$, every allowed domain value solves the equation, not the excluded ones.

Applications and units

Rational equations model combined work rates, travel time, lens formulas, electrical resistance, and inverse variation. Define variables and units before solving.

Context may add restrictions beyond denominators: time, speed, length, and count are often positive. Algebraic candidates must satisfy both mathematical and contextual domains.

Graphical interpretation

An equation $f(x)=g(x)$ asks where two graphs intersect. Vertical asymptotes and holes can explain excluded candidates or a lack of solutions.

Graphing is a useful check, but exact solutions require algebra when the question asks for exact form.

A structured solution routine

  1. Factor denominators if needed.
  2. Record all restrictions.
  3. Identify the LCD.
  4. Multiply every term by the LCD.
  5. Solve the resulting equation.
  6. reject forbidden or contextually invalid values.
  7. verify in the original equation.

Common mistakes

Writing restrictions after cancelling. Use original denominators.

Multiplying only the fractions by the LCD. Every term must be multiplied.

Cross multiplying an equation with more than one fraction per side without combining first. Use the full LCD method.

Keeping an excluded candidate. A zero denominator is never allowed.

Checking only the cleared equation. Verify in the original.

Quick self-check

  • Which inputs make an original denominator zero?
  • Is the LCD fully factored and complete?
  • Did every term receive the multiplier?
  • Are all resulting candidates in the domain?
  • Do they satisfy the original equation and context?
Check your understanding

Try it yourself

Hints are part of learning. Open one whenever it makes the next step feel possible.

1 practice question
Question 1Clear a rational denominator · Gentle

Solve 2/(x − 1) + 1 = 5/(x − 1).

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