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Probability and StatisticsGrades 5–8Grades 9–12University3 min read

Probability

Probability quantifies uncertainty from impossible to certain and connects sample spaces, long-run frequency, counting, and decision making.

Cheat sheet
Probability assigns a number from $0$ to $1$ to an event: $0$ is impossible, $1$ is certain, and values between describe uncertainty.

Outcomes, events, and sample spaces

An outcome is one possible result. The sample space $S$ contains every possible outcome. An event $A$ is a collection of outcomes of interest.

For one fair six-sided die, $S=\{1,2,3,4,5,6\}$. The event “roll an even number” is $A=\{2,4,6\}$.

Equally likely outcomes

When all outcomes are equally likely,

$$ P(A)=\frac{\text{favourable outcomes}}{\text{total outcomes}}. $$

For the even-number event, $P(A)=3/6=1/2$. This shortcut fails when outcomes are not equally likely, such as a biased spinner with unequal sectors.

Experimental probability

Experimental probability uses observed frequency:

$$ \hat P(A)=\frac{\text{number of times }A\text{ occurs}}{\text{number of trials}}. $$

As independent trials accumulate under stable conditions, relative frequency often settles near theoretical probability. Short runs can vary widely; ten coin flips need not contain exactly five heads.

Complements

The complement $A^c$ means that $A$ does not occur:

$$ P(A^c)=1-P(A). $$

Addition rule

For any events $A$ and $B$,

$$ P(A\cup B)=P(A)+P(B)-P(A\cap B). $$

The intersection is subtracted because it was counted twice. If events are mutually exclusive, they cannot occur together and $P(A\cap B)=0$.

Multiplication and independence

For independent events, one event does not change the probability of the other:

$$ P(A\cap B)=P(A)P(B). $$

Two fair coin flips are independent, so $P(\text{two heads})=(1/2)(1/2)=1/4$. Drawing two cards without replacement is not independent because the first draw changes the deck.

Conditional probability

Conditional probability restricts attention to cases where $B$ occurred:

$$ P(A\mid B)=\frac{P(A\cap B)}{P(B)},\qquad P(B)>0. $$

The denominator changes from the entire sample space to event $B$. Tables and tree diagrams help preserve that new reference group.

Counting systematically

Tree diagrams, organized lists, and the fundamental counting principle prevent missed or duplicated outcomes. If one choice has $3$ options and a following independent choice has $4$, there are $3\times4=12$ ordered combinations.

Interpreting probability

A probability of $0.8$ does not promise an event on the next trial. It describes a model or long-run tendency. Evaluate how the probability was estimated, whether assumptions are reasonable, and whether the source has uncertainty or bias.

Common mistakes

Assuming outcomes are equally likely without justification. Use geometry, mechanics, or data to support the model.

Adding overlapping events without subtracting the intersection. Watch for double counting.

Confusing mutually exclusive and independent. Nontrivial mutually exclusive events cannot be independent.

Believing short runs must match theory exactly. Random variation is expected.

Quick self-check

  • Have I defined the sample space and event?
  • Are outcomes equally likely?
  • Do events overlap, exclude one another, or act independently?
  • Would a complement, table, or tree make counting safer?
  • Does the final probability lie from $0$ to $1$?

Explore the idea

Probability sampler

Change one quantity at a time and connect what moves to Probability.

Works offline

success other outcome

What the model is showing Static example: with probability 0.50 over 20 trials, the expected count is 10 and the binomial variance is 5. A single observed count can differ.
Check your understanding

Try it yourself

Hints are part of learning. Open one whenever it makes the next step feel possible.

1 practice question
Question 1Find an equally likely probability · Gentle

A fair six-sided die is rolled. What is the probability of an even result?

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