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Probability and StatisticsGrades 9–123 min read

Expected Value

Expected value is the probability-weighted long-run average of a random variable.

Cheat sheet
Expected value balances every possible outcome by how often the model says it should occur in the long run.

Definition

For a discrete random variable $X$ with possible values $x_i$,

$$ E[X]=\mu=\sum_i x_iP(X=x_i). $$

Multiply each value by its probability, then add. The probabilities must represent a complete valid distribution.

Long-run interpretation

If the random process is repeated independently many times under stable conditions, the average outcome tends to approach $E[X]$.

Expected value need not be a possible single outcome. The expected number on a fair die is $3.5$, even though no roll shows $3.5$.

Worked example: a simple game

This does not mean each play earns ten cents; it describes the long-run average.

Fair games

A game is mathematically fair to the player when the expected net gain is zero. Positive expectation favours the player; negative expectation favours the organizer.

Include entry costs and all payouts consistently. A prize amount is not the same as net gain if the player paid to enter.

Expected value from counts

If outcomes are equally likely, probabilities can be obtained from counts. For a fair six-sided die,

$$ E[X]=\frac{1+2+3+4+5+6}{6}=3.5. $$

For unequal probabilities, a simple arithmetic average of possible values is incorrect; use the weights.

Linearity of expectation

For constants $a,b$,

$$ E[aX+b]=aE[X]+b. $$

More generally,

$$ E[X+Y]=E[X]+E[Y] $$

even when $X$ and $Y$ are not independent. Independence is needed for some variance rules, not for this sum rule.

Binomial expectation

If $X\sim\operatorname{Bin}(n,p)$ counts successes in $n$ independent trials, then

$$ E[X]=np. $$

This makes sense: each trial contributes expected success count $p$, and the expected counts add over $n$ trials.

Decision-making and risk

Expected value compares average financial or quantitative outcomes, but it does not capture spread, worst-case consequences, utility, or ability to tolerate loss.

Two choices can have the same mean and very different variance. High-stakes decisions require more than expectation alone.

Empirical expected value

Observed data can estimate expectation using a weighted average of values by relative frequency. The estimate may vary from sample to sample and may be biased if data collection is unrepresentative.

Distinguish the theoretical model mean from a sample mean used to estimate it.

Insurance interpretation

Insurance pools many uncertain losses. An expected claim cost helps set premiums, but administrative costs, capital requirements, risk, and profit also matter.

An individual may rationally pay more than expected loss to reduce exposure to a rare severe outcome.

Common mistakes

Averaging possible values without probability weights. Outcomes may not be equally likely.

Using prize instead of net gain. Subtract any cost consistently.

Interpreting expectation as the next outcome. It is a long-run mean.

Ignoring outcomes with zero or negative values. Include the complete distribution.

Choosing solely by expectation when risk matters. Compare variability and consequences too.

Quick self-check

  • Are all possible values and probabilities included?
  • Do the probabilities sum to $1$?
  • Are losses represented with negative signs and costs included?
  • Is the result interpreted as a long-run average?
  • Does a binomial setting permit the shortcut $np$?
  • Should variance, feasibility, or risk also influence the decision?

Explore the idea

Probability sampler

Change one quantity at a time and connect what moves to Expected Value.

Works offline

success other outcome

What the model is showing Static example: with probability 0.50 over 20 trials, the expected count is 10 and the binomial variance is 5. A single observed count can differ.
Check your understanding

Try it yourself

Hints are part of learning. Open one whenever it makes the next step feel possible.

1 practice question
Question 1Calculate an expected net gain · Gentle

A game gives a net gain of $5 with probability 0.30 and a net loss of $2 with probability 0.70. Find the expected net gain in dollars.

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