Math101learn.math101.caNormal Distribution
The normal distribution is a symmetric continuous model determined by its mean and standard deviation.
In a normal model, the mean sets the centre and the standard deviation sets the horizontal scale.
Shape and parameters
A normal distribution is bell-shaped, symmetric, unimodal, and continuous. It is determined by
and
We write $X\sim N(\mu,\sigma^2)$ when the second parameter is variance.
Area represents probability
The total area under a probability density curve is $1$. Probability over an interval is the area under the curve above that interval.
Because the model is continuous,
for any exact point. Therefore $P(X<a)=P(X\le a)$ under the ideal continuous model.
Standardizing with z-scores
A z-score tells how many standard deviations a value lies from the mean:
Positive $z$ is above the mean, negative $z$ below, and $z=0$ at the mean. Standardization converts any normal variable to the standard normal distribution $N(0,1)$.
Worked example: interpret a z-score
The percentile is an area, not the z-score itself.
Empirical rule
For a normal distribution, approximately:
- $68\%$ of values lie within $1\sigma$ of the mean;
- $95\%$ lie within $2\sigma$;
- $99.7\%$ lie within $3\sigma$.
This $68$–$95$–$99.7$ rule provides fast estimates and reasonableness checks.
Finding interval probabilities
Convert interval endpoints to z-scores, then use a standard-normal table or technology. Sketch and shade the requested region first.
For a right-tail probability, subtract cumulative left area from $1$. For an interval, subtract the lower cumulative area from the upper one.
Finding a value from a percentile
If a z-score or percentile is known, reverse the standardization:
This can determine cutoffs, warranty thresholds, or score boundaries. Keep the correct tail direction and interpret whether the cutoff is above or below the mean.
Effects of changing parameters
Changing $\mu$ shifts the curve horizontally without changing its shape. Increasing $\sigma$ spreads the same total area across a wider, lower curve; decreasing $\sigma$ makes it narrower and taller.
Area remains $1$ in every case.
Assessing normality
Check a histogram or density plot for approximate symmetry, one central peak, and absence of extreme outliers. A normal probability plot can provide a more formal visual check.
Do not use a normal model solely because a variable is numerical. Many distributions are skewed, bounded, multimodal, or heavy-tailed.
Normal approximation to binomial
When $np$ and $n(1-p)$ are sufficiently large, a binomial count may be approximated normally with
A continuity correction such as $x+0.5$ or $x-0.5$ aligns discrete bars with continuous area.
Common mistakes
Using variance in the z-score denominator. Divide by standard deviation.
Interpreting a z-score as a percentage. Convert it to an area.
Forgetting the right-tail subtraction. Most tables/calculators report left cumulative area.
Assuming every bell-ish sample is exactly normal. Assess fit and context.
Ignoring continuity correction in a binomial approximation. Discrete and continuous boundaries differ.
Quick self-check
- Are $\mu$ and $\sigma$ identified in matching units?
- Does the graph/model appear reasonably normal?
- Is the z-score sign and magnitude sensible?
- Has the requested area been shaded before calculation?
- Is a cumulative area, tail, or interval being reported?
- If reversing a percentile, did I use $x=\mu+z\sigma$ and interpret the cutoff?
Related topics
Try it yourself
Hints are part of learning. Open one whenever it makes the next step feel possible.
Scores have mean 70 and standard deviation 8. What is the z-score for 86?
- z = (86 − 70)/8
- z = 16/8 = 2.
End of lesson
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