Math101learn.math101.caSquare Roots
For $a\ge0$, the principal square root $\sqrt a$ is the unique nonnegative number whose square is $a$. Thus $\sqrt{49}=7$, not $\pm7$.
Square roots reverse squaring and express exact geometric lengths. The principal-root convention prevents ambiguity in functions, while the plus-or-minus distinction matters in equations.
Intuition and core definition
For $a\ge0$, the principal square root $\sqrt a$ is the unique nonnegative number whose square is $a$. Thus $\sqrt{49}=7$, not $\pm7$. The equation $x^2=49$ has two solutions, $x=\pm7$; the radical symbol itself names only the principal root.
Notation, language, and conditions
$\sqrt{a}$ has radicand $a$. Over the real numbers, an even root requires a nonnegative radicand. Perfect squares are $0,1,4,9,16,\ldots$. The identity $\sqrt{a^2}=|a|$ for real $a$, not always $a$, because the principal root must be nonnegative.
Why this idea matters
A principal square root names the nonnegative side length whose square is the radicand, distinct from the two solutions that an equation may have.
A dependable method
- Check the domain: for real square roots, require the radicand to be at least zero.
- Look for a perfect square or factor out the largest perfect-square factor.
- Apply the principal-root convention and keep the result nonnegative.
- If solving $x^2=a$, include both signs when $a>0$.
- Square the proposed principal value and compare with the radicand.
Worked example
Representations and interpretation
A square of area $a$ has side length $\sqrt a$, making the principal root naturally nonnegative. On a graph, $y=\sqrt x$ begins at the origin and is defined only for $x\ge0$ in the real plane.
Reasoning about variations
The rule $\sqrt{a+b}=\sqrt a+\sqrt b$ is generally false: $\sqrt{9+16}=5$ but $3+4=7$. Products can be split as $\sqrt{ab}=\sqrt a\sqrt b$ when $a,b\ge0$, which is why perfect-square factors may be extracted.
Common mistakes
How to check your work
- Square the simplified nonnegative result and recover the radicand.
- Bound a non-perfect root between consecutive perfect squares.
- Confirm that any extracted factor was a perfect square and that the remaining radicand is simplified.
Practice
- Simplify $\sqrt{98}$.
- Evaluate $\sqrt{(-8)^2}$.
- Solve $x^2=36$.
Answers and brief solutions
Show answers
- $7\sqrt2$ $98=49\cdot2$, so $\sqrt{98}=7\sqrt2$.
- $8$ $\sqrt{x^2}=|x|$, so the principal result is $8$.
- $x=\pm6$ Both $6$ and $-6$ square to $36$.
Synthesis and transfer
The diagonal of a rectangular screen follows from a squared-length equation; simplifying the radical preserves an exact length while a decimal gives a practical measurement.
For a screen with width $w$ and height $h$, the diagonal is $d=\sqrt{w^2+h^2}$ and is nonnegative because it represents length. If the squared sum contains a perfect-square factor, simplifying first gives an exact radical that can be rounded only at the final measurement stage. Squaring that result checks the arithmetic and returns $w^2+h^2$. This use of the principal root differs from solving $x^2=d^2$, which may yield both $x=d$ and $x=-d$ algebraically. Context discards the negative physical length, but the distinction should be made explicitly rather than hidden inside the radical symbol.
Related topics
Teaching and accessibility note
Try it yourself
Hints are part of learning. Open one whenever it makes the next step feel possible.
Simplify $\sqrt{98}$.
- $98=49\cdot2$, so $\sqrt{98}=7\sqrt2$.
End of lesson
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