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TrigonometryGrades 9–12University3 min read

Half Angle Identities

Half-angle identities express trig values at $\theta/2$ using functions of $\theta$: $\sin(\theta/2)=\pm\sqrt{(1-\cos\theta)/2}$, $\cos(\theta/2)=\pm\sqrt{(1+\cos\theta)/2}$, and $\tan(\theta/2)=\sin\theta/(1+\cos\theta)=(1-\cos\theta)/\sin\theta$ where denominators are nonzero.

Cheat sheet
Half-angle identities produce exact values, solve equations, and support integration and radical simplification. Quadrant reasoning prevents sign ambiguity.

Intuition and core definition

Half-angle identities express trig values at $\theta/2$ using functions of $\theta$: $\sin(\theta/2)=\pm\sqrt{(1-\cos\theta)/2}$, $\cos(\theta/2)=\pm\sqrt{(1+\cos\theta)/2}$, and $\tan(\theta/2)=\sin\theta/(1+\cos\theta)=(1-\cos\theta)/\sin\theta$ where denominators are nonzero.

Notation, language, and conditions

The square-root sign in sine and cosine formulas carries $\pm$ because the identity gives a magnitude; the quadrant of $\theta/2$ determines sign. The principal square root alone is nonnegative. Tangent also has $\pm\sqrt{(1-\cos\theta)/(1+\cos\theta)}$ with quadrant selection.

Why this idea matters

Half-angle identities recover trigonometric values at a halved angle, with quadrant information deciding the square-root sign.

A dependable method

  1. Determine a coterminal representative for $\theta/2$ and its quadrant.
  2. Select the identity involving the known trig value.
  3. Choose the correct sign from the half-angle quadrant.
  4. Substitute exactly and simplify radicals.
  5. Check with a known unit-circle value or Pythagorean identity.

Worked example

Representations and interpretation

The identities come from solving double-angle formulas such as $\cos(2u)=1-2\sin^2u$ for $\sin u$. Solving a square introduces two signs, and the unit circle selects the appropriate one.

Reasoning about variations

Knowing $\cos\theta$ alone may not determine the quadrant of $\theta/2$ unless the range of $\theta$ is specified. Equivalent tangent half-angle formulas have different excluded denominators but agree on common domains.

Common mistakes

How to check your work

  • Approximate the exact radical and compare with calculator in correct mode.
  • Square sine/cosine half-angle values and verify their sum is $1$.
  • Double the half-angle and check the source cosine value.

Practice

  1. Given $\theta/2$ is in Quadrant I and $\cos\theta=1/2$, find $\sin(\theta/2)$.
  2. Which information determines the $\pm$ sign?
  3. Find $\cos45^\circ$ using half of $90^\circ$.

Answers and brief solutions

Show answers
  1. $\frac12$ $\sqrt{(1-1/2)/2}=\sqrt{1/4}=1/2$.
  2. The quadrant of the half-angle The identity’s radical gives magnitude only.
  3. $\frac{\sqrt2}{2}$ $\sqrt{(1+\cos90^\circ)/2}=\sqrt{1/2}$.

Synthesis and transfer

To obtain an exact value at $15^\circ$, halve a familiar $30^\circ$ angle and choose the positive branch from Quadrant I before simplifying the nested radical.

Using $\cos30^\circ=\sqrt3/2$, the identity gives $\sin15^\circ=\sqrt{(1-\sqrt3/2)/2}=\frac{\sqrt{2-\sqrt3}}2$. The positive root is chosen because $15^\circ$ lies in Quadrant I. Squaring the result and substituting into $2\sin^2(15^\circ)=1-\cos30^\circ$ verifies the radical without relying on a decimal. If the half-angle lay in another quadrant, the same radicand would determine magnitude but not sign. Since halving an angle does not simply halve its sine or cosine, the identity encodes a nonlinear geometric relationship rather than an arithmetic shortcut.

Teaching and accessibility note

Check your understanding

Try it yourself

Hints are part of learning. Open one whenever it makes the next step feel possible.

1 practice question
Question 1Use a half-angle identity · Challenge

Given $\theta/2$ is in Quadrant I and $\cos\theta=1/2$, find $\sin(\theta/2)$.

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