Math101Inverse Laplace Transform
A precise method for recovering time-domain functions using tables, algebra, shifting, and convolution.
Precise definition
The inverse Laplace transform $\mathcal L^{-1}\{F(s)\}=f(t)$ recovers a time-domain function whose Laplace transform is $F(s)$. It is unique up to equality almost everywhere within standard classes such as piecewise-continuous functions of exponential order. Inversion usually uses known pairs and transform properties rather than evaluating the Bromwich integral.
Notation and mathematical language
Core pairs include $1/s\leftrightarrow1$, $1/(s-a)\leftrightarrow e^{at}$, $s/(s^2+\omega^2)\leftrightarrow\cos\omega t$, and $\omega/(s^2+\omega^2)\leftrightarrow\sin\omega t$. The shift $F(s-a)$ corresponds to $e^{at}f(t)$; a factor $e^{-as}$ corresponds to $u(t-a)f(t-a)$.
Conceptual picture
Partial fractions separate a rational transform into recognizable dynamical modes. Completing a square reveals damped sine and cosine terms. A delay factor does not merely shift the graph horizontally; the unit step also keeps the response zero before the delay.
Fully worked example
Interpretation and application
Inverse transforms solve linear initial value problems with impulses, switching, and delays. The recovered function exactly corresponds to the algebraic transform under its assumptions; an engineering input represented by an ideal step or impulse is itself an approximation to a physical signal.
